693. Binary Number with Alternating Bits
class Solution {
public boolean hasAlternatingBits(int n) {
String binary = Integer.toBinaryString(n);
for (int i = 1; i < binary.length(); i++) {
if (binary.charAt(i) == binary.charAt(i - 1))
return false;
}
return true;
}
}
Omar GamalEldeen 