693. Binary Number with Alternating Bits

693. Binary Number with Alternating Bits

class Solution {
    	public boolean hasAlternatingBits(int n) {
		String binary = Integer.toBinaryString(n);

		for (int i = 1; i < binary.length(); i++) {
			if (binary.charAt(i) == binary.charAt(i - 1))
				return false;
		}

		return true;
	}
}
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